Base | Representation |
---|---|
bin | 11110110001001100110… |
… | …101011111101011000011 |
3 | 21111010200002002112012212 |
4 | 132301030311133223003 |
5 | 234120304212021121 |
6 | 4255203052412335 |
7 | 305522060653604 |
oct | 36611465375303 |
9 | 7433602075185 |
10 | 2114413001411 |
11 | 7457990201a7 |
12 | 2a19547770ab |
13 | 1245080c6cc9 |
14 | 744a3bb3dab |
15 | 3a00272b25b |
hex | 1ec4cd5fac3 |
2114413001411 has 4 divisors (see below), whose sum is σ = 2114476429752. Its totient is φ = 2114349573072.
The previous prime is 2114413001287. The next prime is 2114413001461. The reversal of 2114413001411 is 1141003144112.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 2114413001411 - 210 = 2114413000387 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (2114413001461) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 31664141 + ... + 31730846.
It is an arithmetic number, because the mean of its divisors is an integer number (528619107438).
Almost surely, 22114413001411 is an apocalyptic number.
2114413001411 is a deficient number, since it is larger than the sum of its proper divisors (63428341).
2114413001411 is an equidigital number, since it uses as much as digits as its factorization.
2114413001411 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 63428340.
The product of its (nonzero) digits is 384, while the sum is 23.
Adding to 2114413001411 its reverse (1141003144112), we get a palindrome (3255416145523).
The spelling of 2114413001411 in words is "two trillion, one hundred fourteen billion, four hundred thirteen million, one thousand, four hundred eleven".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.067 sec. • engine limits •