Base | Representation |
---|---|
bin | 11110110001001110101… |
… | …001001000001111001001 |
3 | 21111010202012010120102211 |
4 | 132301032221020033021 |
5 | 234120334442022441 |
6 | 4255210054225121 |
7 | 305522606424055 |
oct | 36611651101711 |
9 | 7433665116384 |
10 | 2114443314121 |
11 | 745804144626 |
12 | 2a19629551a1 |
13 | 12451147b418 |
14 | 744a7c24c65 |
15 | 3a005217a81 |
hex | 1ec4ea483c9 |
2114443314121 has 4 divisors (see below), whose sum is σ = 2114455152592. Its totient is φ = 2114431475652.
The previous prime is 2114443314103. The next prime is 2114443314127. The reversal of 2114443314121 is 1214133444112.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 2114443314121 - 217 = 2114443183049 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (2114443314127) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5647155 + ... + 6009928.
It is an arithmetic number, because the mean of its divisors is an integer number (528613788148).
Almost surely, 22114443314121 is an apocalyptic number.
It is an amenable number.
2114443314121 is a deficient number, since it is larger than the sum of its proper divisors (11838471).
2114443314121 is a wasteful number, since it uses less digits than its factorization.
2114443314121 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 11838470.
The product of its digits is 9216, while the sum is 31.
Adding to 2114443314121 its reverse (1214133444112), we get a palindrome (3328576758233).
The spelling of 2114443314121 in words is "two trillion, one hundred fourteen billion, four hundred forty-three million, three hundred fourteen thousand, one hundred twenty-one".
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