Base | Representation |
---|---|
bin | 11110110001111110001… |
… | …010001100101110110001 |
3 | 21111012210202012102221020 |
4 | 132301332022030232301 |
5 | 234124003032344213 |
6 | 4255421133050053 |
7 | 305551426461306 |
oct | 36617612145661 |
9 | 7435722172836 |
10 | 2115240512433 |
11 | 746083141504 |
12 | 2a1b45926929 |
13 | 12460a68ccb9 |
14 | 74541a610ad |
15 | 3a0501d9923 |
hex | 1ec7e28cbb1 |
2115240512433 has 16 divisors (see below), whose sum is σ = 2865153392640. Its totient is φ = 1387873188944.
The previous prime is 2115240512419. The next prime is 2115240512443. The reversal of 2115240512433 is 3342150425112.
It is a cyclic number.
It is not a de Polignac number, because 2115240512433 - 217 = 2115240381361 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 2115240512394 and 2115240512403.
It is not an unprimeable number, because it can be changed into a prime (2115240512443) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 16084593 + ... + 16215566.
It is an arithmetic number, because the mean of its divisors is an integer number (179072087040).
Almost surely, 22115240512433 is an apocalyptic number.
It is an amenable number.
2115240512433 is a deficient number, since it is larger than the sum of its proper divisors (749912880207).
2115240512433 is a wasteful number, since it uses less digits than its factorization.
2115240512433 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 32300508.
The product of its (nonzero) digits is 28800, while the sum is 33.
Adding to 2115240512433 its reverse (3342150425112), we get a palindrome (5457390937545).
The spelling of 2115240512433 in words is "two trillion, one hundred fifteen billion, two hundred forty million, five hundred twelve thousand, four hundred thirty-three".
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