2116262141131 has 4 divisors (see below), whose sum is σ = 2116764701064. Its totient is φ = 2115759581200.

The previous prime is 2116262141101. The next prime is 2116262141137. The reversal of 2116262141131 is 1311412626112.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 2116262141131 - 2⁵ = 2116262141099 is a prime.

It is a super-2 number, since 2×2116262141131² (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 2116262141093 and 2116262141102.

It is not an unprimeable number, because it can be changed into a prime (2116262141137) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 251273650 + ... + 251282071.

It is an arithmetic number, because the mean of its divisors is an integer number (529191175266).

Almost surely, 2^{2116262141131} is an apocalyptic number.

2116262141131 is a deficient number, since it is larger than the sum of its proper divisors (502559933).

2116262141131 is an equidigital number, since it uses as much as digits as its factorization.

2116262141131 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 502559932.

The product of its digits is 3456, while the sum is 31.

Adding to 2116262141131 its reverse (1311412626112), we get a palindrome (3427674767243).

The spelling of 2116262141131 in words is "two trillion, one hundred sixteen billion, two hundred sixty-two million, one hundred forty-one thousand, one hundred thirty-one".