Base | Representation |
---|---|
bin | 1100010100100110011… |
… | …0000100000000000011 |
3 | 202020101220112022010022 |
4 | 3011021212010000003 |
5 | 11432014124042011 |
6 | 241125334524055 |
7 | 21202554156446 |
oct | 3051146040003 |
9 | 666356468108 |
10 | 211688112131 |
11 | 8185a469901 |
12 | 35039b0662b |
13 | 16c67982c62 |
14 | a36251365d |
15 | 578e6388db |
hex | 3149984003 |
211688112131 has 4 divisors (see below), whose sum is σ = 211702154664. Its totient is φ = 211674069600.
The previous prime is 211688112121. The next prime is 211688112133. The reversal of 211688112131 is 131211886112.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 211688112131 - 218 = 211687849987 is a prime.
It is a super-2 number, since 2×2116881121312 (a number of 23 digits) contains 22 as substring.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 211688112091 and 211688112100.
It is not an unprimeable number, because it can be changed into a prime (211688112133) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 6998630 + ... + 7028811.
It is an arithmetic number, because the mean of its divisors is an integer number (52925538666).
Almost surely, 2211688112131 is an apocalyptic number.
211688112131 is a deficient number, since it is larger than the sum of its proper divisors (14042533).
211688112131 is a wasteful number, since it uses less digits than its factorization.
211688112131 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 14042532.
The product of its digits is 4608, while the sum is 35.
Adding to 211688112131 its reverse (131211886112), we get a palindrome (342899998243).
The spelling of 211688112131 in words is "two hundred eleven billion, six hundred eighty-eight million, one hundred twelve thousand, one hundred thirty-one".
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