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211688112131 = 1509114027441
BaseRepresentation
bin1100010100100110011…
…0000100000000000011
3202020101220112022010022
43011021212010000003
511432014124042011
6241125334524055
721202554156446
oct3051146040003
9666356468108
10211688112131
118185a469901
1235039b0662b
1316c67982c62
14a36251365d
15578e6388db
hex3149984003

211688112131 has 4 divisors (see below), whose sum is σ = 211702154664. Its totient is φ = 211674069600.

The previous prime is 211688112121. The next prime is 211688112133. The reversal of 211688112131 is 131211886112.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 211688112131 - 218 = 211687849987 is a prime.

It is a super-2 number, since 2×2116881121312 (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 211688112091 and 211688112100.

It is not an unprimeable number, because it can be changed into a prime (211688112133) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 6998630 + ... + 7028811.

It is an arithmetic number, because the mean of its divisors is an integer number (52925538666).

Almost surely, 2211688112131 is an apocalyptic number.

211688112131 is a deficient number, since it is larger than the sum of its proper divisors (14042533).

211688112131 is a wasteful number, since it uses less digits than its factorization.

211688112131 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 14042532.

The product of its digits is 4608, while the sum is 35.

Adding to 211688112131 its reverse (131211886112), we get a palindrome (342899998243).

The spelling of 211688112131 in words is "two hundred eleven billion, six hundred eighty-eight million, one hundred twelve thousand, one hundred thirty-one".

Divisors: 1 15091 14027441 211688112131