Base | Representation |
---|---|
bin | 110000001101000001100000… |
… | …001101111101010001000001 |
3 | 1000210122010011010201120210120 |
4 | 300031001200031331101001 |
5 | 210241411424200031423 |
6 | 2030520001243450453 |
7 | 62440403240224464 |
oct | 6015014015752101 |
9 | 1023563133646716 |
10 | 212001200002113 |
11 | 616062275a5535 |
12 | 1b93b304b26a29 |
13 | 913a820473b92 |
14 | 3a4ccacb332db |
15 | 19799874eaee3 |
hex | c0d06037d441 |
212001200002113 has 16 divisors (see below), whose sum is σ = 282926875674240. Its totient is φ = 141204832191104.
The previous prime is 212001200002087. The next prime is 212001200002121. The reversal of 212001200002113 is 311200002100212.
It is a cyclic number.
It is not a de Polignac number, because 212001200002113 - 212 = 212001199998017 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 212001200002092 and 212001200002101.
It is not an unprimeable number, because it can be changed into a prime (212001200002313) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 280764445 + ... + 281518517.
It is an arithmetic number, because the mean of its divisors is an integer number (17682929729640).
Almost surely, 2212001200002113 is an apocalyptic number.
It is an amenable number.
212001200002113 is a deficient number, since it is larger than the sum of its proper divisors (70925675672127).
212001200002113 is a wasteful number, since it uses less digits than its factorization.
212001200002113 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 839688.
The product of its (nonzero) digits is 48, while the sum is 15.
Adding to 212001200002113 its reverse (311200002100212), we get a palindrome (523201202102325).
The spelling of 212001200002113 in words is "two hundred twelve trillion, one billion, two hundred million, two thousand, one hundred thirteen".
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