2120013313001 has 4 divisors (see below), whose sum is σ = 2120021784192. Its totient is φ = 2120004841812.

The previous prime is 2120013312997. The next prime is 2120013313039. The reversal of 2120013313001 is 1003133100212.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 2120013313001 - 2² = 2120013312997 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (2120013313601) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3848405 + ... + 4364658.

It is an arithmetic number, because the mean of its divisors is an integer number (530005446048).

Almost surely, 2^{2120013313001} is an apocalyptic number.

It is an amenable number.

2120013313001 is a deficient number, since it is larger than the sum of its proper divisors (8471191).

2120013313001 is an equidigital number, since it uses as much as digits as its factorization.

2120013313001 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 8471190.

The product of its (nonzero) digits is 108, while the sum is 17.

Adding to 2120013313001 its reverse (1003133100212), we get a palindrome (3123146413213).

The spelling of 2120013313001 in words is "two trillion, one hundred twenty billion, thirteen million, three hundred thirteen thousand, one".