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21200231113 = 31683878423
BaseRepresentation
bin10011101111101000…
…011101101011001001
32000201110222022210221
4103233220131223021
5321404224343423
613423402310041
71350234663655
oct235750355311
960643868727
1021200231113
118a99a83466
124137ab8321
131ccb250369
141051875a65
158412eee5d
hex4efa1dac9

21200231113 has 4 divisors (see below), whose sum is σ = 21884109568. Its totient is φ = 20516352660.

The previous prime is 21200231077. The next prime is 21200231131. The reversal of 21200231113 is 31113200212.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-21200231113 is a prime.

It is a super-2 number, since 2×212002311132 (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (21200231713) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 341939181 + ... + 341939242.

It is an arithmetic number, because the mean of its divisors is an integer number (5471027392).

Almost surely, 221200231113 is an apocalyptic number.

It is an amenable number.

21200231113 is a deficient number, since it is larger than the sum of its proper divisors (683878455).

21200231113 is an equidigital number, since it uses as much as digits as its factorization.

21200231113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 683878454.

The product of its (nonzero) digits is 72, while the sum is 16.

Adding to 21200231113 its reverse (31113200212), we get a palindrome (52313431325).

The spelling of 21200231113 in words is "twenty-one billion, two hundred million, two hundred thirty-one thousand, one hundred thirteen".

Divisors: 1 31 683878423 21200231113