Base | Representation |
---|---|
bin | 110000001101001101011011… |
… | …110001110101101100110011 |
3 | 1000210200100012220210110010201 |
4 | 300031031123301311230303 |
5 | 210242114143132032430 |
6 | 2030525520343340031 |
7 | 62441335552062544 |
oct | 6015153361655463 |
9 | 1023610186713121 |
10 | 212014010424115 |
11 | 61610700766159 |
12 | 1b94189b151617 |
13 | 913bab249a243 |
14 | 3a4d7662304cb |
15 | 1979e86ea18ca |
hex | c0d35bc75b33 |
212014010424115 has 16 divisors (see below), whose sum is σ = 267807529728000. Its totient is φ = 160684087437792.
The previous prime is 212014010424109. The next prime is 212014010424119. The reversal of 212014010424115 is 511424010410212.
It is not a de Polignac number, because 212014010424115 - 27 = 212014010423987 is a prime.
It is a super-2 number, since 2×2120140104241152 (a number of 29 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (212014010424119) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 137372014 + ... + 138906796.
It is an arithmetic number, because the mean of its divisors is an integer number (16737970608000).
Almost surely, 2212014010424115 is an apocalyptic number.
212014010424115 is a deficient number, since it is larger than the sum of its proper divisors (55793519303885).
212014010424115 is a wasteful number, since it uses less digits than its factorization.
212014010424115 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2988906.
The product of its (nonzero) digits is 2560, while the sum is 28.
Adding to 212014010424115 its reverse (511424010410212), we get a palindrome (723438020834327).
The spelling of 212014010424115 in words is "two hundred twelve trillion, fourteen billion, ten million, four hundred twenty-four thousand, one hundred fifteen".
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