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212014010424115 = 51914540991534783
BaseRepresentation
bin110000001101001101011011…
…110001110101101100110011
31000210200100012220210110010201
4300031031123301311230303
5210242114143132032430
62030525520343340031
762441335552062544
oct6015153361655463
91023610186713121
10212014010424115
1161610700766159
121b94189b151617
13913bab249a243
143a4d7662304cb
151979e86ea18ca
hexc0d35bc75b33

212014010424115 has 16 divisors (see below), whose sum is σ = 267807529728000. Its totient is φ = 160684087437792.

The previous prime is 212014010424109. The next prime is 212014010424119. The reversal of 212014010424115 is 511424010410212.

It is not a de Polignac number, because 212014010424115 - 27 = 212014010423987 is a prime.

It is a super-2 number, since 2×2120140104241152 (a number of 29 digits) contains 22 as substring.

It is not an unprimeable number, because it can be changed into a prime (212014010424119) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 137372014 + ... + 138906796.

It is an arithmetic number, because the mean of its divisors is an integer number (16737970608000).

Almost surely, 2212014010424115 is an apocalyptic number.

212014010424115 is a deficient number, since it is larger than the sum of its proper divisors (55793519303885).

212014010424115 is a wasteful number, since it uses less digits than its factorization.

212014010424115 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2988906.

The product of its (nonzero) digits is 2560, while the sum is 28.

Adding to 212014010424115 its reverse (511424010410212), we get a palindrome (723438020834327).

The spelling of 212014010424115 in words is "two hundred twelve trillion, fourteen billion, ten million, four hundred twenty-four thousand, one hundred fifteen".

Divisors: 1 5 19 95 1454099 1534783 7270495 7673915 27627881 29160877 138139405 145804385 2231726425517 11158632127585 42402802084823 212014010424115