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212030342433 = 3271319611391607
BaseRepresentation
bin1100010101110111111…
…1100100010100100001
3202021021202111101211200
43011131333210110201
511433214231424213
6241223322031413
721214211113440
oct3053577442441
9667252441750
10212030342433
1181a15667568
1235114648569
1316cc08487b0
14a395b5ad57
1557ae6da273
hex315dfe4521

212030342433 has 192 divisors, whose sum is σ = 406440652800. Its totient is φ = 103402759680.

The previous prime is 212030342417. The next prime is 212030342441. The reversal of 212030342433 is 334243030212.

212030342433 is a `hidden beast` number, since 2 + 1 + 203 + 0 + 3 + 424 + 33 = 666.

It is not a de Polignac number, because 212030342433 - 24 = 212030342417 is a prime.

It is a super-2 number, since 2×2120303424332 (a number of 23 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 212030342397 and 212030342406.

It is not an unprimeable number, because it can be changed into a prime (212030342453) by changing a digit.

It is a polite number, since it can be written in 191 ways as a sum of consecutive naturals, for example, 131940916 + ... + 131942522.

It is an arithmetic number, because the mean of its divisors is an integer number (2116878400).

Almost surely, 2212030342433 is an apocalyptic number.

It is an amenable number.

212030342433 is a deficient number, since it is larger than the sum of its proper divisors (194410310367).

212030342433 is a wasteful number, since it uses less digits than its factorization.

212030342433 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1852 (or 1849 counting only the distinct ones).

The product of its (nonzero) digits is 10368, while the sum is 27.

Adding to 212030342433 its reverse (334243030212), we get a palindrome (546273372645).

The spelling of 212030342433 in words is "two hundred twelve billion, thirty million, three hundred forty-two thousand, four hundred thirty-three".