Base | Representation |
---|---|
bin | 11110110110111110011… |
… | …010010101011010101001 |
3 | 21111201200012100000121222 |
4 | 132312332122111122221 |
5 | 234221004020421213 |
6 | 4302110225511425 |
7 | 306131530632431 |
oct | 36667632253251 |
9 | 7451605300558 |
10 | 2120613451433 |
11 | 748390011064 |
12 | 2a2ba51a2575 |
13 | 124c85876b49 |
14 | 748d14812c1 |
15 | 3a266c5b808 |
hex | 1edbe6956a9 |
2120613451433 has 16 divisors (see below), whose sum is σ = 2149857230976. Its totient is φ = 2091542705280.
The previous prime is 2120613451391. The next prime is 2120613451441. The reversal of 2120613451433 is 3341543160212.
It is a cyclic number.
It is not a de Polignac number, because 2120613451433 - 210 = 2120613450409 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 2120613451393 and 2120613451402.
It is not an unprimeable number, because it can be changed into a prime (2120613051433) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 71911910 + ... + 71941392.
It is an arithmetic number, because the mean of its divisors is an integer number (134366076936).
Almost surely, 22120613451433 is an apocalyptic number.
It is an amenable number.
2120613451433 is a deficient number, since it is larger than the sum of its proper divisors (29243779543).
2120613451433 is a wasteful number, since it uses less digits than its factorization.
2120613451433 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 32384.
The product of its (nonzero) digits is 51840, while the sum is 35.
The spelling of 2120613451433 in words is "two trillion, one hundred twenty billion, six hundred thirteen million, four hundred fifty-one thousand, four hundred thirty-three".
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