Base | Representation |
---|---|
bin | 11110110110111111011… |
… | …101101110010101100001 |
3 | 21111201201102120112102220 |
4 | 132312333131232111201 |
5 | 234221023031222103 |
6 | 4302112100301253 |
7 | 306132134040123 |
oct | 36667735562541 |
9 | 7451642515386 |
10 | 2120631117153 |
11 | 748399a8762a |
12 | 2a2bab0a1829 |
13 | 124c89420933 |
14 | 748d395d213 |
15 | 3a26859ac53 |
hex | 1edbf76e561 |
2120631117153 has 4 divisors (see below), whose sum is σ = 2827508156208. Its totient is φ = 1413754078100.
The previous prime is 2120631117151. The next prime is 2120631117161. The reversal of 2120631117153 is 3517111360212.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 2120631117153 - 21 = 2120631117151 is a prime.
It is not an unprimeable number, because it can be changed into a prime (2120631117151) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 353438519523 + ... + 353438519528.
It is an arithmetic number, because the mean of its divisors is an integer number (706877039052).
Almost surely, 22120631117153 is an apocalyptic number.
It is an amenable number.
2120631117153 is a deficient number, since it is larger than the sum of its proper divisors (706877039055).
2120631117153 is an equidigital number, since it uses as much as digits as its factorization.
2120631117153 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 706877039054.
The product of its (nonzero) digits is 7560, while the sum is 33.
Adding to 2120631117153 its reverse (3517111360212), we get a palindrome (5637742477365).
The spelling of 2120631117153 in words is "two trillion, one hundred twenty billion, six hundred thirty-one million, one hundred seventeen thousand, one hundred fifty-three".
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