Base | Representation |
---|---|
bin | 11110110111100010101… |
… | …100001100001110000011 |
3 | 21111210020121122012010210 |
4 | 132313202230030032003 |
5 | 234223230330042011 |
6 | 4302250451325203 |
7 | 306152601312423 |
oct | 36674254141603 |
9 | 7453217565123 |
10 | 2121222112131 |
11 | 748672644931 |
12 | 2a3134bb0803 |
13 | 1250519b57c5 |
14 | 7494c240483 |
15 | 3a2a03da6a6 |
hex | 1ede2b0c383 |
2121222112131 has 4 divisors (see below), whose sum is σ = 2828296149512. Its totient is φ = 1414148074752.
The previous prime is 2121222112067. The next prime is 2121222112171. The reversal of 2121222112131 is 1312112221212.
It is a semiprime because it is the product of two primes.
It is not a de Polignac number, because 2121222112131 - 26 = 2121222112067 is a prime.
It is a super-2 number, since 2×21212221121312 (a number of 25 digits) contains 22 as substring.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 2121222112098 and 2121222112107.
It is not an unprimeable number, because it can be changed into a prime (2121222112171) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 353537018686 + ... + 353537018691.
It is an arithmetic number, because the mean of its divisors is an integer number (707074037378).
Almost surely, 22121222112131 is an apocalyptic number.
2121222112131 is a deficient number, since it is larger than the sum of its proper divisors (707074037381).
2121222112131 is an equidigital number, since it uses as much as digits as its factorization.
2121222112131 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 707074037380.
The product of its digits is 192, while the sum is 21.
Adding to 2121222112131 its reverse (1312112221212), we get a palindrome (3433334333343).
The spelling of 2121222112131 in words is "two trillion, one hundred twenty-one billion, two hundred twenty-two million, one hundred twelve thousand, one hundred thirty-one".
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