21213010000001 has 4 divisors (see below), whose sum is σ = 21282107752752. Its totient is φ = 21143912247252.

The previous prime is 21213009999997. The next prime is 21213010000009. The reversal of 21213010000001 is 10000001031212.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 21213010000001 - 2² = 21213009999997 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (21213010000009) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 34548875915 + ... + 34548876528.

It is an arithmetic number, because the mean of its divisors is an integer number (5320526938188).

Almost surely, 2^{21213010000001} is an apocalyptic number.

It is an amenable number.

21213010000001 is a deficient number, since it is larger than the sum of its proper divisors (69097752751).

21213010000001 is an equidigital number, since it uses as much as digits as its factorization.

21213010000001 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 69097752750.

The product of its (nonzero) digits is 12, while the sum is 11.

Adding to 21213010000001 its reverse (10000001031212), we get a palindrome (31213011031213).

The spelling of 21213010000001 in words is "twenty-one trillion, two hundred thirteen billion, ten million, one", and thus it is an aban number.