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212131433 = 297314877
BaseRepresentation
bin11001010010011…
…01111001101001
3112210011101121202
430221031321221
5413301201213
633014413545
75154041663
oct1451157151
9483141552
10212131433
11a9819538
125b0612b5
1334c44077
142025d533
1513953b58
hexca4de69

212131433 has 4 divisors (see below), whose sum is σ = 219446340. Its totient is φ = 204816528.

The previous prime is 212131421. The next prime is 212131453. The reversal of 212131433 is 334131212.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 172843609 + 39287824 = 13147^2 + 6268^2 .

It is a cyclic number.

It is not a de Polignac number, because 212131433 - 222 = 207937129 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (212131453) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3657410 + ... + 3657467.

It is an arithmetic number, because the mean of its divisors is an integer number (54861585).

Almost surely, 2212131433 is an apocalyptic number.

It is an amenable number.

212131433 is a deficient number, since it is larger than the sum of its proper divisors (7314907).

212131433 is an equidigital number, since it uses as much as digits as its factorization.

212131433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 7314906.

The product of its digits is 432, while the sum is 20.

The square root of 212131433 is about 14564.7325069841. The cubic root of 212131433 is about 596.3963935494.

Adding to 212131433 its reverse (334131212), we get a palindrome (546262645).

The spelling of 212131433 in words is "two hundred twelve million, one hundred thirty-one thousand, four hundred thirty-three".

Divisors: 1 29 7314877 212131433