212140403433 has 16 divisors (see below), whose sum is σ = 359179519360. Its totient is φ = 121223087568.

The previous prime is 212140403407. The next prime is 212140403443. The reversal of 212140403433 is 334304041212.

212140403433 is a `hidden beast` number, since 2 + 1 + 214 + 0 + 403 + 43 + 3 = 666.

212140403433 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is not a de Polignac number, because 212140403433 - 2⁹ = 212140402921 is a prime.

It is a Harshad number since it is a multiple of its sum of digits (27).

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 212140403397 and 212140403406.

It is not an unprimeable number, because it can be changed into a prime (212140403443) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 561217810 + ... + 561218187.

It is an arithmetic number, because the mean of its divisors is an integer number (22448719960).

Almost surely, 2^212140403433 is an apocalyptic number.

It is an amenable number.

212140403433 is a deficient number, since it is larger than the sum of its proper divisors (147039115927).

212140403433 is a wasteful number, since it uses less digits than its factorization.

212140403433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1122436013 (or 1122436007 counting only the distinct ones).

The product of its (nonzero) digits is 6912, while the sum is 27.

Adding to 212140403433 its reverse (334304041212), we get a palindrome (546444444645).

The spelling of 212140403433 in words is "two hundred twelve billion, one hundred forty million, four hundred three thousand, four hundred thirty-three".