Base | Representation |
---|---|
bin | 1001101001011010001110… |
… | …11001011011111111110011 |
3 | 2210010001011000101212012211 |
4 | 10310231013121123333303 |
5 | 10240032324034404210 |
6 | 113041332425032551 |
7 | 4316443502022061 |
oct | 464550731337763 |
9 | 83101130355184 |
10 | 21214041325555 |
11 | 6839908308911 |
12 | 246750b625757 |
13 | bab6249195b0 |
14 | 534a9d539031 |
15 | 26bc5c61938a |
hex | 134b4765bff3 |
21214041325555 has 16 divisors (see below), whose sum is σ = 27415206292320. Its totient is φ = 15665675021568.
The previous prime is 21214041325511. The next prime is 21214041325591. The reversal of 21214041325555 is 55552314041212.
It is not a de Polignac number, because 21214041325555 - 211 = 21214041323507 is a prime.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 14401311 + ... + 15805879.
It is an arithmetic number, because the mean of its divisors is an integer number (1713450393270).
Almost surely, 221214041325555 is an apocalyptic number.
21214041325555 is a deficient number, since it is larger than the sum of its proper divisors (6201164966765).
21214041325555 is a wasteful number, since it uses less digits than its factorization.
21214041325555 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1636950.
The product of its (nonzero) digits is 240000, while the sum is 40.
Adding to 21214041325555 its reverse (55552314041212), we get a palindrome (76766355366767).
The spelling of 21214041325555 in words is "twenty-one trillion, two hundred fourteen billion, forty-one million, three hundred twenty-five thousand, five hundred fifty-five".
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