Base | Representation |
---|---|
bin | 110000010000010001010011… |
… | …110111101010100110111011 |
3 | 1000211102110002112022101100020 |
4 | 300100101103313222212323 |
5 | 210304040412232200243 |
6 | 2031210302314141523 |
7 | 62462462523434130 |
oct | 6020212367524673 |
9 | 1024373075271306 |
10 | 212224331131323 |
11 | 61691919279445 |
12 | 1b9765b71218a3 |
13 | 915588ca74954 |
14 | 3a599d8cb8587 |
15 | 1980696533283 |
hex | c10453dea9bb |
212224331131323 has 16 divisors (see below), whose sum is σ = 332129712556800. Its totient is φ = 117993450512736.
The previous prime is 212224331131321. The next prime is 212224331131381. The reversal of 212224331131323 is 323131133422212.
212224331131323 is digitally balanced in base 2 and base 4, because in such bases it contains all the possibile digits an equal number of times.
It is not a de Polignac number, because 212224331131323 - 21 = 212224331131321 is a prime.
It is not an unprimeable number, because it can be changed into a prime (212224331131321) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 136566492873 + ... + 136566494426.
It is an arithmetic number, because the mean of its divisors is an integer number (20758107034800).
Almost surely, 2212224331131323 is an apocalyptic number.
212224331131323 is a deficient number, since it is larger than the sum of its proper divisors (119905381425477).
212224331131323 is a wasteful number, since it uses less digits than its factorization.
212224331131323 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 273132987346.
The product of its digits is 31104, while the sum is 33.
Adding to 212224331131323 its reverse (323131133422212), we get a palindrome (535355464553535).
The spelling of 212224331131323 in words is "two hundred twelve trillion, two hundred twenty-four billion, three hundred thirty-one million, one hundred thirty-one thousand, three hundred twenty-three".
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