Base | Representation |
---|---|
bin | 1001101001111000001101… |
… | …00110100111101000101001 |
3 | 2210011120200112212002111001 |
4 | 10310330012212213220221 |
5 | 10240313303314144431 |
6 | 113052553341435001 |
7 | 4320553341431650 |
oct | 464740646475051 |
9 | 83146615762431 |
10 | 21230134131241 |
11 | 6845716280a22 |
12 | 246a660b6ba61 |
13 | baccba997819 |
14 | 535788948197 |
15 | 26c3a0342e61 |
hex | 134f069a7a29 |
21230134131241 has 8 divisors (see below), whose sum is σ = 24570137150720. Its totient is φ = 17966912790528.
The previous prime is 21230134131223. The next prime is 21230134131251. The reversal of 21230134131241 is 14213143103212.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 21230134131241 - 213 = 21230134123049 is a prime.
It is not an unprimeable number, because it can be changed into a prime (21230134131251) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 19195419096 + ... + 19195420201.
It is an arithmetic number, because the mean of its divisors is an integer number (3071267143840).
Almost surely, 221230134131241 is an apocalyptic number.
It is an amenable number.
21230134131241 is a deficient number, since it is larger than the sum of its proper divisors (3340003019479).
21230134131241 is an equidigital number, since it uses as much as digits as its factorization.
21230134131241 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 38390839383.
The product of its (nonzero) digits is 3456, while the sum is 28.
Adding to 21230134131241 its reverse (14213143103212), we get a palindrome (35443277234453).
The spelling of 21230134131241 in words is "twenty-one trillion, two hundred thirty billion, one hundred thirty-four million, one hundred thirty-one thousand, two hundred forty-one".
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