21240413500331 has 4 divisors (see below), whose sum is σ = 21240423537000. Its totient is φ = 21240403463664.

The previous prime is 21240413500309. The next prime is 21240413500351. The reversal of 21240413500331 is 13300531404212.

It is a semiprime because it is the product of two primes, and also a brilliant number, because the two primes have the same length.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-21240413500331 is a prime.

It is a super-2 number, since 2×21240413500331² (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 21240413500294 and 21240413500303.

It is not an unprimeable number, because it can be changed into a prime (21240413500351) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 469481 + ... + 6534618.

It is an arithmetic number, because the mean of its divisors is an integer number (5310105884250).

Almost surely, 2^{21240413500331} is an apocalyptic number.

21240413500331 is a deficient number, since it is larger than the sum of its proper divisors (10036669).

21240413500331 is an equidigital number, since it uses as much as digits as its factorization.

21240413500331 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 10036668.

The product of its (nonzero) digits is 8640, while the sum is 29.

Adding to 21240413500331 its reverse (13300531404212), we get a palindrome (34540944904543).

The spelling of 21240413500331 in words is "twenty-one trillion, two hundred forty billion, four hundred thirteen million, five hundred thousand, three hundred thirty-one".