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21242231433 = 3222031071379
BaseRepresentation
bin10011110010001000…
…101011101010001001
32000211102000011102100
4103302020223222021
5322001002401213
613431502424013
71351254662613
oct236210535211
960742004370
1021242231433
11901075a975
124149b92009
132006b67517
141057289db3
15844d49773
hex4f222ba89

21242231433 has 12 divisors (see below), whose sum is σ = 30697179760. Its totient is φ = 14155046136.

The previous prime is 21242231393. The next prime is 21242231441. The reversal of 21242231433 is 33413224212.

21242231433 is a `hidden beast` number, since 2 + 1 + 2 + 4 + 223 + 1 + 433 = 666.

It is not a de Polignac number, because 21242231433 - 26 = 21242231369 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 21242231397 and 21242231406.

It is not an unprimeable number, because it can be changed into a prime (21262231433) by changing a digit.

It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 515863 + ... + 555516.

Almost surely, 221242231433 is an apocalyptic number.

It is an amenable number.

21242231433 is a deficient number, since it is larger than the sum of its proper divisors (9454948327).

21242231433 is a wasteful number, since it uses less digits than its factorization.

21242231433 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1073588 (or 1073585 counting only the distinct ones).

The product of its digits is 6912, while the sum is 27.

Adding to 21242231433 its reverse (33413224212), we get a palindrome (54655455645).

The spelling of 21242231433 in words is "twenty-one billion, two hundred forty-two million, two hundred thirty-one thousand, four hundred thirty-three".

Divisors: 1 3 9 2203 6609 19827 1071379 3214137 9642411 2360247937 7080743811 21242231433