Base | Representation |
---|---|
bin | 1100010111010111111… |
… | …1100111110111010011 |
3 | 202022022211012001002010 |
4 | 3011311333213313103 |
5 | 11440030322311011 |
6 | 241331304354003 |
7 | 21230200535646 |
oct | 3056577476723 |
9 | 668284161063 |
10 | 212433010131 |
11 | 82101994791 |
12 | 35207475903 |
13 | 170560b23c4 |
14 | a3d3417a5d |
15 | 57d4c291a6 |
hex | 3175fe7dd3 |
212433010131 has 16 divisors (see below), whose sum is σ = 287245373184. Its totient is φ = 139628336544.
The previous prime is 212433010103. The next prime is 212433010189. The reversal of 212433010131 is 131010334212.
It is not a de Polignac number, because 212433010131 - 25 = 212433010099 is a prime.
It is a super-2 number, since 2×2124330101312 (a number of 23 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 212433010098 and 212433010107.
It is not an unprimeable number, because it can be changed into a prime (212433010831) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 754656 + ... + 997181.
It is an arithmetic number, because the mean of its divisors is an integer number (17952835824).
Almost surely, 2212433010131 is an apocalyptic number.
212433010131 is a deficient number, since it is larger than the sum of its proper divisors (74812363053).
212433010131 is a wasteful number, since it uses less digits than its factorization.
212433010131 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1752410.
The product of its (nonzero) digits is 432, while the sum is 21.
Adding to 212433010131 its reverse (131010334212), we get a palindrome (343443344343).
The spelling of 212433010131 in words is "two hundred twelve billion, four hundred thirty-three million, ten thousand, one hundred thirty-one".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.069 sec. • engine limits •