Base | Representation |
---|---|
bin | 11110111010100000111… |
… | …100110001111100101011 |
3 | 21112002111001222121020022 |
4 | 132322200330301330223 |
5 | 234301300004211021 |
6 | 4303535315351055 |
7 | 306324651115013 |
oct | 36724074617453 |
9 | 7462431877208 |
10 | 2124414132011 |
11 | 749a60437696 |
12 | 2a3885bb248b |
13 | 1254400bbc72 |
14 | 74b7214cc43 |
15 | 3a3da75e1ab |
hex | 1eea0f31f2b |
2124414132011 has 4 divisors (see below), whose sum is σ = 2124426191472. Its totient is φ = 2124402072552.
The previous prime is 2124414131981. The next prime is 2124414132017. The reversal of 2124414132011 is 1102314144212.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 2124414132011 - 214 = 2124414115627 is a prime.
It is a super-3 number, since 3×21244141320113 (a number of 38 digits) contains 333 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (2124414132017) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5761511 + ... + 6119136.
It is an arithmetic number, because the mean of its divisors is an integer number (531106547868).
Almost surely, 22124414132011 is an apocalyptic number.
2124414132011 is a deficient number, since it is larger than the sum of its proper divisors (12059461).
2124414132011 is a wasteful number, since it uses less digits than its factorization.
2124414132011 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 12059460.
The product of its (nonzero) digits is 1536, while the sum is 26.
Adding to 2124414132011 its reverse (1102314144212), we get a palindrome (3226728276223).
The spelling of 2124414132011 in words is "two trillion, one hundred twenty-four billion, four hundred fourteen million, one hundred thirty-two thousand, eleven".
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