Base | Representation |
---|---|
bin | 110000011011100011101110… |
… | …001011011000011101010011 |
3 | 1000221011121021012200011110012 |
4 | 300123203232023120131103 |
5 | 210404243012102320103 |
6 | 2033002504452225135 |
7 | 62602512625062011 |
oct | 6033435613303523 |
9 | 1027147235604405 |
10 | 213000014104403 |
11 | 61960887076979 |
12 | 1ba809b590b1ab |
13 | 91b0a79b450a6 |
14 | 3a8538187b8b1 |
15 | 1995944ab02d8 |
hex | c1b8ee2d8753 |
213000014104403 has 16 divisors (see below), whose sum is σ = 214935652515840. Its totient is φ = 211068554953536.
The previous prime is 213000014104387. The next prime is 213000014104439. The reversal of 213000014104403 is 304401410000312.
It is a cyclic number.
It is not a de Polignac number, because 213000014104403 - 24 = 213000014104387 is a prime.
It is a super-4 number, since 4×2130000141044034 (a number of 58 digits) contains 4444 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (213000014100403) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 383933750 + ... + 384488132.
It is an arithmetic number, because the mean of its divisors is an integer number (13433478282240).
Almost surely, 2213000014104403 is an apocalyptic number.
213000014104403 is a deficient number, since it is larger than the sum of its proper divisors (1935638411437).
213000014104403 is a wasteful number, since it uses less digits than its factorization.
213000014104403 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 558146.
The product of its (nonzero) digits is 1152, while the sum is 23.
Adding to 213000014104403 its reverse (304401410000312), we get a palindrome (517401424104715).
The spelling of 213000014104403 in words is "two hundred thirteen trillion, fourteen million, one hundred four thousand, four hundred three".
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