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2130011133113 = 2239551619431
BaseRepresentation
bin11110111111101110100…
…011101001010010111001
321112121221010201201100102
4132333232203221102321
5234344230322224423
64310302534445145
7306613442621333
oct36775643512271
97477833651312
102130011133113
11751372834436
122a49885037b5
13125b22836436
1475143616453
153a616cdec28
hex1efee8e94b9

2130011133113 has 4 divisors (see below), whose sum is σ = 2139562752768. Its totient is φ = 2120459513460.

The previous prime is 2130011133083. The next prime is 2130011133119. The reversal of 2130011133113 is 3113311100312.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-2130011133113 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (2130011133119) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4775809493 + ... + 4775809938.

It is an arithmetic number, because the mean of its divisors is an integer number (534890688192).

Almost surely, 22130011133113 is an apocalyptic number.

It is an amenable number.

2130011133113 is a deficient number, since it is larger than the sum of its proper divisors (9551619655).

2130011133113 is an equidigital number, since it uses as much as digits as its factorization.

2130011133113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 9551619654.

The product of its (nonzero) digits is 162, while the sum is 20.

Adding to 2130011133113 its reverse (3113311100312), we get a palindrome (5243322233425).

The spelling of 2130011133113 in words is "two trillion, one hundred thirty billion, eleven million, one hundred thirty-three thousand, one hundred thirteen".

Divisors: 1 223 9551619431 2130011133113