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213001113441 = 371000371147
BaseRepresentation
bin1100011001011111011…
…0110000111101100001
3202100210102011200022110
43012113312300331201
511442211241112231
6241503521025533
721250236406554
oct3062766607541
9670712150273
10213001113441
1182373637156
12353457852a9
13171169c08cc
14a448a5a69b
155819a46046
hex3197db0f61

213001113441 has 4 divisors (see below), whose sum is σ = 284001484592. Its totient is φ = 142000742292.

The previous prime is 213001113433. The next prime is 213001113509. The reversal of 213001113441 is 144311100312.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 213001113441 - 23 = 213001113433 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (213001113041) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 35500185571 + ... + 35500185576.

It is an arithmetic number, because the mean of its divisors is an integer number (71000371148).

Almost surely, 2213001113441 is an apocalyptic number.

It is an amenable number.

213001113441 is a deficient number, since it is larger than the sum of its proper divisors (71000371151).

213001113441 is an equidigital number, since it uses as much as digits as its factorization.

213001113441 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 71000371150.

The product of its (nonzero) digits is 288, while the sum is 21.

Adding to 213001113441 its reverse (144311100312), we get a palindrome (357312213753).

The spelling of 213001113441 in words is "two hundred thirteen billion, one million, one hundred thirteen thousand, four hundred forty-one".

Divisors: 1 3 71000371147 213001113441