21300312113 has 4 divisors (see below), whose sum is σ = 21302030400. Its totient is φ = 21298593828.

The previous prime is 21300312091. The next prime is 21300312119. The reversal of 21300312113 is 31121300312.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 21300312113 - 2⁶ = 21300312049 is a prime.

It is a super-2 number, since 2×21300312113² (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 21300312091 and 21300312100.

It is not an unprimeable number, because it can be changed into a prime (21300312119) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 840413 + ... + 865386.

It is an arithmetic number, because the mean of its divisors is an integer number (5325507600).

Almost surely, 2^21300312113 is an apocalyptic number.

It is an amenable number.

21300312113 is a deficient number, since it is larger than the sum of its proper divisors (1718287).

21300312113 is a wasteful number, since it uses less digits than its factorization.

21300312113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1718286.

The product of its (nonzero) digits is 108, while the sum is 17.

Adding to 21300312113 its reverse (31121300312), we get a palindrome (52421612425).

The spelling of 21300312113 in words is "twenty-one billion, three hundred million, three hundred twelve thousand, one hundred thirteen".