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2130122113 = 7304303159
BaseRepresentation
bin111111011110111…
…0001010110000001
312111110012102012121
41332331301112001
513330302401423
6551211524241
7103533511360
oct17675612601
95443172177
102130122113
119a34422a9
124b5459681
1327c4065b2
14162c8b7d7
15c701745d
hex7ef71581

2130122113 has 4 divisors (see below), whose sum is σ = 2434425280. Its totient is φ = 1825818948.

The previous prime is 2130122107. The next prime is 2130122143. The reversal of 2130122113 is 3112210312.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-2130122113 is a prime.

It is not an unprimeable number, because it can be changed into a prime (2130122143) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 152151573 + ... + 152151586.

It is an arithmetic number, because the mean of its divisors is an integer number (608606320).

Almost surely, 22130122113 is an apocalyptic number.

It is an amenable number.

2130122113 is a deficient number, since it is larger than the sum of its proper divisors (304303167).

2130122113 is an equidigital number, since it uses as much as digits as its factorization.

2130122113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 304303166.

The product of its (nonzero) digits is 72, while the sum is 16.

The square root of 2130122113 is about 46153.2459638539. The cubic root of 2130122113 is about 1286.6729386240.

Adding to 2130122113 its reverse (3112210312), we get a palindrome (5242332425).

The spelling of 2130122113 in words is "two billion, one hundred thirty million, one hundred twenty-two thousand, one hundred thirteen".

Divisors: 1 7 304303159 2130122113