Search a number
-
+
21302112113 = 32576540409
BaseRepresentation
bin10011110101101101…
…000110111101110001
32000222120200102021022
4103311231012331301
5322111320041423
613441442105225
71352612652062
oct236555067561
960876612238
1021302112113
11904153a137
12416604b215
1320163a2089
1410611d6569
1584a226dc8
hex4f5b46f71

21302112113 has 4 divisors (see below), whose sum is σ = 21308655780. Its totient is φ = 21295568448.

The previous prime is 21302112109. The next prime is 21302112173. The reversal of 21302112113 is 31121120312.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 12857972449 + 8444139664 = 113393^2 + 91892^2 .

It is a cyclic number.

It is not a de Polignac number, because 21302112113 - 22 = 21302112109 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 21302112091 and 21302112100.

It is not an unprimeable number, because it can be changed into a prime (21302112103) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3266948 + ... + 3273461.

It is an arithmetic number, because the mean of its divisors is an integer number (5327163945).

Almost surely, 221302112113 is an apocalyptic number.

It is an amenable number.

21302112113 is a deficient number, since it is larger than the sum of its proper divisors (6543667).

21302112113 is an equidigital number, since it uses as much as digits as its factorization.

21302112113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 6543666.

The product of its (nonzero) digits is 72, while the sum is 17.

Adding to 21302112113 its reverse (31121120312), we get a palindrome (52423232425).

The spelling of 21302112113 in words is "twenty-one billion, three hundred two million, one hundred twelve thousand, one hundred thirteen".

Divisors: 1 3257 6540409 21302112113