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213022001113 = 254383767991
BaseRepresentation
bin1100011001100100011…
…0011100011111011001
3202100211212110212210221
43012121012130133121
511442232113013423
6241505544440041
721250612063555
oct3063106343731
9670755425727
10213022001113
1182384403399
1235350779021
131711b12508c
14a44b736865
15581b7bee5d
hex319919c7d9

213022001113 has 4 divisors (see below), whose sum is σ = 213105771648. Its totient is φ = 212938230580.

The previous prime is 213022001107. The next prime is 213022001117. The reversal of 213022001113 is 311100220312.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-213022001113 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (213022001117) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 41881453 + ... + 41886538.

It is an arithmetic number, because the mean of its divisors is an integer number (53276442912).

Almost surely, 2213022001113 is an apocalyptic number.

It is an amenable number.

213022001113 is a deficient number, since it is larger than the sum of its proper divisors (83770535).

213022001113 is an equidigital number, since it uses as much as digits as its factorization.

213022001113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 83770534.

The product of its (nonzero) digits is 72, while the sum is 16.

Adding to 213022001113 its reverse (311100220312), we get a palindrome (524122221425).

The spelling of 213022001113 in words is "two hundred thirteen billion, twenty-two million, one thousand, one hundred thirteen".

Divisors: 1 2543 83767991 213022001113