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21302442343403 = 131638649411031
BaseRepresentation
bin1001101011111110111001…
…00000100011101111101011
32210102111022211111212011222
410311333130200203233223
510243004400214442103
6113150112405412255
74326023244205064
oct465773440435753
983374284455158
1021302442343403
116873351392a51
122480680a0a08b
13bb6a723a1190
14539087d2956b
1526e1d33e8638
hex135fdc823beb

21302442343403 has 4 divisors (see below), whose sum is σ = 22941091754448. Its totient is φ = 19663792932360.

The previous prime is 21302442343387. The next prime is 21302442343417. The reversal of 21302442343403 is 30434324420312.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 21302442343403 - 24 = 21302442343387 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (21302442343433) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 819324705503 + ... + 819324705528.

It is an arithmetic number, because the mean of its divisors is an integer number (5735272938612).

Almost surely, 221302442343403 is an apocalyptic number.

21302442343403 is a deficient number, since it is larger than the sum of its proper divisors (1638649411045).

21302442343403 is a wasteful number, since it uses less digits than its factorization.

21302442343403 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1638649411044.

The product of its (nonzero) digits is 165888, while the sum is 35.

Adding to 21302442343403 its reverse (30434324420312), we get a palindrome (51736766763715).

The spelling of 21302442343403 in words is "twenty-one trillion, three hundred two billion, four hundred forty-two million, three hundred forty-three thousand, four hundred three".

Divisors: 1 13 1638649411031 21302442343403