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213100012001 = 1439148088959
BaseRepresentation
bin1100011001110111000…
…0000010000111100001
3202101001022021020122002
43012131300002013201
511442412100341001
6241521412453345
721252550133552
oct3063560020741
9671038236562
10213100012001
11824144460a8
123537291a255
1317131339c76
14a457c42329
15582357e46b
hex319dc021e1

213100012001 has 4 divisors (see below), whose sum is σ = 213248102400. Its totient is φ = 212951921604.

The previous prime is 213100011961. The next prime is 213100012003. The reversal of 213100012001 is 100210001312.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-213100012001 is a prime.

It is a super-2 number, since 2×2131000120012 (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (213100012003) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 74043041 + ... + 74045918.

It is an arithmetic number, because the mean of its divisors is an integer number (53312025600).

Almost surely, 2213100012001 is an apocalyptic number.

It is an amenable number.

213100012001 is a deficient number, since it is larger than the sum of its proper divisors (148090399).

213100012001 is a wasteful number, since it uses less digits than its factorization.

213100012001 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 148090398.

The product of its (nonzero) digits is 12, while the sum is 11.

Adding to 213100012001 its reverse (100210001312), we get a palindrome (313310013313).

The spelling of 213100012001 in words is "two hundred thirteen billion, one hundred million, twelve thousand, one".

Divisors: 1 1439 148088959 213100012001