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213101113 = 349161043
BaseRepresentation
bin11001011001110…
…10101000111001
3112211222122202211
430230322220321
5414023213423
633051255121
75165221021
oct1454725071
9484878684
10213101113
11aa321025
125b44a4a1
13351c3544
1420432a81
1513a9610d
hexcb3aa39

213101113 has 4 divisors (see below), whose sum is σ = 213165648. Its totient is φ = 213036580.

The previous prime is 213101087. The next prime is 213101123. The reversal of 213101113 is 311101312.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 213101113 - 25 = 213101081 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 213101093 and 213101102.

It is not an unprimeable number, because it can be changed into a prime (213101123) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 27031 + ... + 34012.

It is an arithmetic number, because the mean of its divisors is an integer number (53291412).

Almost surely, 2213101113 is an apocalyptic number.

It is an amenable number.

213101113 is a deficient number, since it is larger than the sum of its proper divisors (64535).

213101113 is an equidigital number, since it uses as much as digits as its factorization.

213101113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 64534.

The product of its (nonzero) digits is 18, while the sum is 13.

The square root of 213101113 is about 14597.9831826181. The cubic root of 213101113 is about 597.3037472212.

Adding to 213101113 its reverse (311101312), we get a palindrome (524202425).

The spelling of 213101113 in words is "two hundred thirteen million, one hundred one thousand, one hundred thirteen".

Divisors: 1 3491 61043 213101113