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2131013433 = 3710337811
BaseRepresentation
bin111111100000100…
…1010111100111001
312111111212200212110
41333001022330321
513331014412213
6551243002533
7103544213103
oct17701127471
95444780773
102131013433
119a39a0a2a
124b5809449
1327c6591c3
14163040573
15c71415c3
hex7f04af39

2131013433 has 4 divisors (see below), whose sum is σ = 2841351248. Its totient is φ = 1420675620.

The previous prime is 2131013431. The next prime is 2131013441. The reversal of 2131013433 is 3343101312.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 2131013433 - 21 = 2131013431 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (2131013431) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 355168903 + ... + 355168908.

It is an arithmetic number, because the mean of its divisors is an integer number (710337812).

Almost surely, 22131013433 is an apocalyptic number.

It is an amenable number.

2131013433 is a deficient number, since it is larger than the sum of its proper divisors (710337815).

2131013433 is an equidigital number, since it uses as much as digits as its factorization.

2131013433 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 710337814.

The product of its (nonzero) digits is 648, while the sum is 21.

The square root of 2131013433 is about 46162.9010461864. The cubic root of 2131013433 is about 1286.8523770694.

Adding to 2131013433 its reverse (3343101312), we get a palindrome (5474114745).

It can be divided in two parts, 21310 and 13433, that added together give a palindrome (34743).

The spelling of 2131013433 in words is "two billion, one hundred thirty-one million, thirteen thousand, four hundred thirty-three".

Divisors: 1 3 710337811 2131013433