Base | Representation |
---|---|
bin | 110000011101001010100001… |
… | …110101000010110110010011 |
3 | 1000221120011012100121001020012 |
4 | 300131022201311002312103 |
5 | 210413100100444030003 |
6 | 2033125322311105135 |
7 | 62613501302364353 |
oct | 6035124165026623 |
9 | 1027504170531205 |
10 | 213110402330003 |
11 | 619a368337a692 |
12 | 1ba9a2826721ab |
13 | 91bb2bc8c0189 |
14 | 3a8a85443cb63 |
15 | 1998755ce28d8 |
hex | c1d2a1d42d93 |
213110402330003 has 4 divisors (see below), whose sum is σ = 224326739294760. Its totient is φ = 201894065365248.
The previous prime is 213110402329969. The next prime is 213110402330039. The reversal of 213110402330003 is 300033204011312.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 213110402330003 - 210 = 213110402328979 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (213110402230003) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5608168482350 + ... + 5608168482387.
It is an arithmetic number, because the mean of its divisors is an integer number (56081684823690).
Almost surely, 2213110402330003 is an apocalyptic number.
213110402330003 is a deficient number, since it is larger than the sum of its proper divisors (11216336964757).
213110402330003 is a wasteful number, since it uses less digits than its factorization.
213110402330003 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 11216336964756.
The product of its (nonzero) digits is 1296, while the sum is 23.
Adding to 213110402330003 its reverse (300033204011312), we get a palindrome (513143606341315).
The spelling of 213110402330003 in words is "two hundred thirteen trillion, one hundred ten billion, four hundred two million, three hundred thirty thousand, three".
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