Base | Representation |
---|---|
bin | 11111000000110110000… |
… | …101111101110001010011 |
3 | 21112202000210002010120010 |
4 | 133000312011331301103 |
5 | 234404210043442321 |
6 | 4311022010450003 |
7 | 306655255153632 |
oct | 37006605756123 |
9 | 7482023063503 |
10 | 2131211312211 |
11 | 751929252793 |
12 | 2a5062433903 |
13 | 125c84391297 |
14 | 75218b91519 |
15 | 3a687363676 |
hex | 1f03617dc53 |
2131211312211 has 4 divisors (see below), whose sum is σ = 2841615082952. Its totient is φ = 1420807541472.
The previous prime is 2131211312183. The next prime is 2131211312231. The reversal of 2131211312211 is 1122131121312.
It is a semiprime because it is the product of two primes.
It is not a de Polignac number, because 2131211312211 - 26 = 2131211312147 is a prime.
It is a super-2 number, since 2×21312113122112 (a number of 25 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (2131211312231) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 355201885366 + ... + 355201885371.
It is an arithmetic number, because the mean of its divisors is an integer number (710403770738).
Almost surely, 22131211312211 is an apocalyptic number.
2131211312211 is a deficient number, since it is larger than the sum of its proper divisors (710403770741).
2131211312211 is an equidigital number, since it uses as much as digits as its factorization.
2131211312211 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 710403770740.
The product of its digits is 144, while the sum is 21.
Adding to 2131211312211 its reverse (1122131121312), we get a palindrome (3253342433523).
The spelling of 2131211312211 in words is "two trillion, one hundred thirty-one billion, two hundred eleven million, three hundred twelve thousand, two hundred eleven".
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