Base | Representation |
---|---|
bin | 11111000000110110001… |
… | …101001010101101010011 |
3 | 21112202000220122001102001 |
4 | 133000312031022231103 |
5 | 234404211034401321 |
6 | 4311022115134431 |
7 | 306655310206204 |
oct | 37006615125523 |
9 | 7482026561361 |
10 | 2131213200211 |
11 | 75192a322217 |
12 | 2a5062ba4417 |
13 | 125c848a2744 |
14 | 752191235ab |
15 | 3a6875d7c91 |
hex | 1f03634ab53 |
2131213200211 has 4 divisors (see below), whose sum is σ = 2131404918912. Its totient is φ = 2131021481512.
The previous prime is 2131213200209. The next prime is 2131213200289. The reversal of 2131213200211 is 1120023121312.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 2131213200211 - 21 = 2131213200209 is a prime.
It is a super-2 number, since 2×21312132002112 (a number of 25 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (2131213000211) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 95842675 + ... + 95864908.
It is an arithmetic number, because the mean of its divisors is an integer number (532851229728).
Almost surely, 22131213200211 is an apocalyptic number.
2131213200211 is a deficient number, since it is larger than the sum of its proper divisors (191718701).
2131213200211 is a wasteful number, since it uses less digits than its factorization.
2131213200211 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 191718700.
The product of its (nonzero) digits is 144, while the sum is 19.
Adding to 2131213200211 its reverse (1120023121312), we get a palindrome (3251236321523).
The spelling of 2131213200211 in words is "two trillion, one hundred thirty-one billion, two hundred thirteen million, two hundred thousand, two hundred eleven".
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