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213122231263139 = 1173265407510913
BaseRepresentation
bin110000011101010101100010…
…111000110101111110100011
31000221121021201201211002221212
4300131111202320311332203
5210413243312200410024
62033135000150140335
762614400365560032
oct6035254270657643
91027537651732855
10213122231263139
11619a86a3510190
121baa06240516ab
1391bc45648abb3
143a8b25744a719
151998be9521a0e
hexc1d562e35fa3

213122231263139 has 8 divisors (see below), whose sum is σ = 235681869691632. Its totient is φ = 191093407856640.

The previous prime is 213122231263129. The next prime is 213122231263147. The reversal of 213122231263139 is 931362132221312.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 213122231263139 - 224 = 213122214485923 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 213122231263096 and 213122231263105.

It is not an unprimeable number, because it can be changed into a prime (213122231263129) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 132703754654 + ... + 132703756259.

It is an arithmetic number, because the mean of its divisors is an integer number (29460233711454).

Almost surely, 2213122231263139 is an apocalyptic number.

213122231263139 is a deficient number, since it is larger than the sum of its proper divisors (22559638428493).

213122231263139 is a wasteful number, since it uses less digits than its factorization.

213122231263139 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 265407510997.

The product of its digits is 139968, while the sum is 41.

The spelling of 213122231263139 in words is "two hundred thirteen trillion, one hundred twenty-two billion, two hundred thirty-one million, two hundred sixty-three thousand, one hundred thirty-nine".

Divisors: 1 11 73 803 265407510913 2919482620043 19374748296649 213122231263139