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2131231100113 = 5981701950767
BaseRepresentation
bin11111000000110111010…
…001011100110011010001
321112202002011022110110101
4133000313101130303101
5234404230130200423
64311023554532401
7306655615310413
oct37006721346321
97482064273411
102131231100113
11751939438725
122a5068b97101
13125c884cbcbb
147521b6629b3
153a688e717ad
hex1f03745ccd1

2131231100113 has 8 divisors (see below), whose sum is σ = 2131933115520. Its totient is φ = 2130529212240.

The previous prime is 2131231100111. The next prime is 2131231100149. The reversal of 2131231100113 is 3110011321312.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 2131231100113 - 21 = 2131231100111 is a prime.

It is a super-2 number, since 2×21312311001132 (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (2131231100111) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 41955256 + ... + 42006022.

It is an arithmetic number, because the mean of its divisors is an integer number (266491639440).

Almost surely, 22131231100113 is an apocalyptic number.

It is an amenable number.

2131231100113 is a deficient number, since it is larger than the sum of its proper divisors (702015407).

2131231100113 is an equidigital number, since it uses as much as digits as its factorization.

2131231100113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 63767.

The product of its (nonzero) digits is 108, while the sum is 19.

Adding to 2131231100113 its reverse (3110011321312), we get a palindrome (5241242421425).

The spelling of 2131231100113 in words is "two trillion, one hundred thirty-one billion, two hundred thirty-one million, one hundred thousand, one hundred thirteen".

Divisors: 1 5981 7019 50767 41980639 303637427 356333573 2131231100113