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213124413235 = 542624882647
BaseRepresentation
bin1100011001111100110…
…1000111011100110011
3202101010000011221211111
43012133031013130303
511442434322210420
6241524043454151
721253264423306
oct3063715073463
9671100157744
10213124413235
11824271a2108
123537ab27357
1317136401776
14a45b194b3d
15582579e45a
hex319f347733

213124413235 has 4 divisors (see below), whose sum is σ = 255749295888. Its totient is φ = 170499530584.

The previous prime is 213124413181. The next prime is 213124413253. The reversal of 213124413235 is 532314421312.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 213124413235 - 225 = 213090858803 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 213124413197 and 213124413206.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 21312441319 + ... + 21312441328.

It is an arithmetic number, because the mean of its divisors is an integer number (63937323972).

Almost surely, 2213124413235 is an apocalyptic number.

213124413235 is a deficient number, since it is larger than the sum of its proper divisors (42624882653).

213124413235 is an equidigital number, since it uses as much as digits as its factorization.

213124413235 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 42624882652.

The product of its digits is 17280, while the sum is 31.

Adding to 213124413235 its reverse (532314421312), we get a palindrome (745438834547).

The spelling of 213124413235 in words is "two hundred thirteen billion, one hundred twenty-four million, four hundred thirteen thousand, two hundred thirty-five".

Divisors: 1 5 42624882647 213124413235