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21313143121 = 149263543883
BaseRepresentation
bin10011110110010111…
…001100000101010001
32001000100102211222011
4103312113030011101
5322122131034441
613442514342521
71353105504334
oct236627140521
961010384864
1021313143121
119047793976
12416988aa41
132018764cba
14106286861b
1584b1a5581
hex4f65cc151

21313143121 has 8 divisors (see below), whose sum is σ = 21537806400. Its totient is φ = 21089568432.

The previous prime is 21313143073. The next prime is 21313143143. The reversal of 21313143121 is 12134131312.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-21313143121 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 21313143092 and 21313143101.

It is not an unprimeable number, because it can be changed into a prime (21313143521) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 232755 + ... + 311128.

It is an arithmetic number, because the mean of its divisors is an integer number (2692225800).

Almost surely, 221313143121 is an apocalyptic number.

It is an amenable number.

21313143121 is a deficient number, since it is larger than the sum of its proper divisors (224663279).

21313143121 is a wasteful number, since it uses less digits than its factorization.

21313143121 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 544295.

The product of its digits is 432, while the sum is 22.

Adding to 21313143121 its reverse (12134131312), we get a palindrome (33447274433).

The spelling of 21313143121 in words is "twenty-one billion, three hundred thirteen million, one hundred forty-three thousand, one hundred twenty-one".

Divisors: 1 149 263 39187 543883 81038567 143041229 21313143121