Base | Representation |
---|---|
bin | 11111000000111101001… |
… | …011001100000110000001 |
3 | 21112202100001122022002212 |
4 | 133000331023030012001 |
5 | 234404431002401423 |
6 | 4311041453151505 |
7 | 306661230060323 |
oct | 37007513140601 |
9 | 7482301568085 |
10 | 2131330122113 |
11 | 75198a321395 |
12 | 2a509618b595 |
13 | 125ca2b8c5ba |
14 | 7522a87b613 |
15 | 3a6929d1578 |
hex | 1f03d2cc181 |
2131330122113 has 4 divisors (see below), whose sum is σ = 2131830556080. Its totient is φ = 2130829688148.
The previous prime is 2131330122079. The next prime is 2131330122149. The reversal of 2131330122113 is 3112210331312.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 2131330122113 - 26 = 2131330122049 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (2131330121113) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 250210595 + ... + 250219112.
It is an arithmetic number, because the mean of its divisors is an integer number (532957639020).
Almost surely, 22131330122113 is an apocalyptic number.
It is an amenable number.
2131330122113 is a deficient number, since it is larger than the sum of its proper divisors (500433967).
2131330122113 is an equidigital number, since it uses as much as digits as its factorization.
2131330122113 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 500433966.
The product of its (nonzero) digits is 648, while the sum is 23.
Adding to 2131330122113 its reverse (3112210331312), we get a palindrome (5243540453425).
The spelling of 2131330122113 in words is "two trillion, one hundred thirty-one billion, three hundred thirty million, one hundred twenty-two thousand, one hundred thirteen".
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