Base | Representation |
---|---|
bin | 11111000000111101111… |
… | …110000110010000011001 |
3 | 21112202100222202022121010 |
4 | 133000331332012100121 |
5 | 234404442411430140 |
6 | 4311043051204133 |
7 | 306661451362305 |
oct | 37007576062031 |
9 | 7482328668533 |
10 | 2131343467545 |
11 | 751996906a76 |
12 | 2a509a746649 |
13 | 125ca5882ac6 |
14 | 7522c552d05 |
15 | 3a693c6a880 |
hex | 1f03df86419 |
2131343467545 has 16 divisors (see below), whose sum is σ = 3466053640512. Its totient is φ = 1118081818560.
The previous prime is 2131343467471. The next prime is 2131343467619. The reversal of 2131343467545 is 5457643431312.
It is an interprime number because it is at equal distance from previous prime (2131343467471) and next prime (2131343467619).
It is not a de Polignac number, because 2131343467545 - 28 = 2131343467289 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 2131343467494 and 2131343467503.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 1164667647 + ... + 1164669476.
It is an arithmetic number, because the mean of its divisors is an integer number (216628352532).
Almost surely, 22131343467545 is an apocalyptic number.
It is an amenable number.
2131343467545 is a deficient number, since it is larger than the sum of its proper divisors (1334710172967).
2131343467545 is a wasteful number, since it uses less digits than its factorization.
2131343467545 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 2329337192.
The product of its digits is 3628800, while the sum is 48.
Adding to 2131343467545 its reverse (5457643431312), we get a palindrome (7588986898857).
The spelling of 2131343467545 in words is "two trillion, one hundred thirty-one billion, three hundred forty-three million, four hundred sixty-seven thousand, five hundred forty-five".
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