Base | Representation |
---|---|
bin | 111111100001010… |
… | …1001010110110001 |
3 | 12111112121100021221 |
4 | 1333002221112301 |
5 | 13331114300423 |
6 | 551255145041 |
7 | 103550413333 |
oct | 17702512661 |
9 | 5445540257 |
10 | 2131400113 |
11 | 9a41354a7 |
12 | 4b5975181 |
13 | 27c7631cb |
14 | 163101453 |
15 | c71bae5d |
hex | 7f0a95b1 |
2131400113 has 4 divisors (see below), whose sum is σ = 2137024240. Its totient is φ = 2125775988.
The previous prime is 2131400111. The next prime is 2131400119. The reversal of 2131400113 is 3110041312.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 2131400113 - 21 = 2131400111 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (2131400111) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2811495 + ... + 2812252.
It is an arithmetic number, because the mean of its divisors is an integer number (534256060).
Almost surely, 22131400113 is an apocalyptic number.
It is an amenable number.
2131400113 is a deficient number, since it is larger than the sum of its proper divisors (5624127).
2131400113 is an equidigital number, since it uses as much as digits as its factorization.
2131400113 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 5624126.
The product of its (nonzero) digits is 72, while the sum is 16.
The square root of 2131400113 is about 46167.0890678631. The cubic root of 2131400113 is about 1286.9302070157.
Adding to 2131400113 its reverse (3110041312), we get a palindrome (5241441425).
The spelling of 2131400113 in words is "two billion, one hundred thirty-one million, four hundred thousand, one hundred thirteen".
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