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21314081 = 31687551
BaseRepresentation
bin101000101001…
…1101000100001
31111002212102102
41101103220201
520424022311
62040500145
7346111115
oct121235041
944085372
1021314081
1111038648
12717a655
1345535a9
142b8b745
151d1043b
hex1453a21

21314081 has 4 divisors (see below), whose sum is σ = 22001664. Its totient is φ = 20626500.

The previous prime is 21314053. The next prime is 21314087. The reversal of 21314081 is 18041312.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 21314081 - 222 = 17119777 is a prime.

It is a super-2 number, since 2×213140812 = 908580097749122, which contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (21314087) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 343745 + ... + 343806.

It is an arithmetic number, because the mean of its divisors is an integer number (5500416).

Almost surely, 221314081 is an apocalyptic number.

It is an amenable number.

21314081 is a deficient number, since it is larger than the sum of its proper divisors (687583).

21314081 is an equidigital number, since it uses as much as digits as its factorization.

21314081 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 687582.

The product of its (nonzero) digits is 192, while the sum is 20.

The square root of 21314081 is about 4616.7175568796. The cubic root of 21314081 is about 277.2610544906.

Adding to 21314081 its reverse (18041312), we get a palindrome (39355393).

The spelling of 21314081 in words is "twenty-one million, three hundred fourteen thousand, eighty-one".

Divisors: 1 31 687551 21314081