Base | Representation |
---|---|
bin | 11111000001000011011… |
… | …000100111100000010011 |
3 | 21112202121022200100220212 |
4 | 133001003120213200103 |
5 | 234410134140234210 |
6 | 4311100054154335 |
7 | 306663633445202 |
oct | 37010330474023 |
9 | 7482538610825 |
10 | 2131434305555 |
11 | 751a3310aa05 |
12 | 2a51050529ab |
13 | 125cbb6392c9 |
14 | 7523a63b239 |
15 | 3a69bc10805 |
hex | 1f043627813 |
2131434305555 has 8 divisors (see below), whose sum is σ = 2557778050800. Its totient is φ = 1705109521696.
The previous prime is 2131434305551. The next prime is 2131434305579. The reversal of 2131434305555 is 5555034341312.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 2131434305555 - 22 = 2131434305551 is a prime.
It is not an unprimeable number, because it can be changed into a prime (2131434305551) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 4491860 + ... + 4943649.
It is an arithmetic number, because the mean of its divisors is an integer number (319722256350).
Almost surely, 22131434305555 is an apocalyptic number.
2131434305555 is a deficient number, since it is larger than the sum of its proper divisors (426343745245).
2131434305555 is an equidigital number, since it uses as much as digits as its factorization.
2131434305555 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 9480693.
The product of its (nonzero) digits is 540000, while the sum is 41.
Adding to 2131434305555 its reverse (5555034341312), we get a palindrome (7686468646867).
The spelling of 2131434305555 in words is "two trillion, one hundred thirty-one billion, four hundred thirty-four million, three hundred five thousand, five hundred fifty-five".
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