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21314411131 = 131639570087
BaseRepresentation
bin10011110110011100…
…000001101001111011
32001000102211021100111
4103312130001221323
5322122442124011
613443001445151
71353122335216
oct236634015173
961012737314
1021314411131
11904847a612
12416a1a07b7
132018aba1c0
141062ab877d
1584b356121
hex4f6701a7b

21314411131 has 4 divisors (see below), whose sum is σ = 22953981232. Its totient is φ = 19674841032.

The previous prime is 21314411117. The next prime is 21314411141. The reversal of 21314411131 is 13111441312.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 21314411131 - 215 = 21314378363 is a prime.

It is a super-2 number, since 2×213144111312 (a number of 21 digits) contains 22 as substring.

It is not an unprimeable number, because it can be changed into a prime (21314411141) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 819785031 + ... + 819785056.

It is an arithmetic number, because the mean of its divisors is an integer number (5738495308).

Almost surely, 221314411131 is an apocalyptic number.

21314411131 is a deficient number, since it is larger than the sum of its proper divisors (1639570101).

21314411131 is a wasteful number, since it uses less digits than its factorization.

21314411131 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1639570100.

The product of its digits is 288, while the sum is 22.

Adding to 21314411131 its reverse (13111441312), we get a palindrome (34425852443).

The spelling of 21314411131 in words is "twenty-one billion, three hundred fourteen million, four hundred eleven thousand, one hundred thirty-one".

Divisors: 1 13 1639570087 21314411131