Base | Representation |
---|---|
bin | 11111000001010111010… |
… | …011000101111001110001 |
3 | 21112210110121100012102112 |
4 | 133001113103011321301 |
5 | 234411330202322041 |
6 | 4311153151055105 |
7 | 310005131303003 |
oct | 37012723057161 |
9 | 7483417305375 |
10 | 2131768401521 |
11 | 752094762180 |
12 | 2a5198b11495 |
13 | 126042914525 |
14 | 7526cb68373 |
15 | 3a6bb206deb |
hex | 1f0574c5e71 |
2131768401521 has 4 divisors (see below), whose sum is σ = 2325565528944. Its totient is φ = 1937971274100.
The previous prime is 2131768401463. The next prime is 2131768401527. The reversal of 2131768401521 is 1251048671312.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 2131768401521 - 210 = 2131768400497 is a prime.
It is a super-2 number, since 2×21317684015212 (a number of 25 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (2131768401527) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 96898563695 + ... + 96898563716.
It is an arithmetic number, because the mean of its divisors is an integer number (581391382236).
Almost surely, 22131768401521 is an apocalyptic number.
It is an amenable number.
2131768401521 is a deficient number, since it is larger than the sum of its proper divisors (193797127423).
2131768401521 is a wasteful number, since it uses less digits than its factorization.
2131768401521 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 193797127422.
The product of its (nonzero) digits is 80640, while the sum is 41.
The spelling of 2131768401521 in words is "two trillion, one hundred thirty-one billion, seven hundred sixty-eight million, four hundred one thousand, five hundred twenty-one".
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