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2132413403 = 4152010083
BaseRepresentation
bin111111100011010…
…0000101111011011
312111121111211021012
41333012200233123
513331344212103
6551333004135
7103562133461
oct17706405733
95447454235
102132413403
119a476782a
124b618364b
1327ca294a3
141632c6831
15c731b2d8
hex7f1a0bdb

2132413403 has 4 divisors (see below), whose sum is σ = 2184423528. Its totient is φ = 2080403280.

The previous prime is 2132413391. The next prime is 2132413441. The reversal of 2132413403 is 3043142312.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-2132413403 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (2132413103) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 26005001 + ... + 26005082.

It is an arithmetic number, because the mean of its divisors is an integer number (546105882).

Almost surely, 22132413403 is an apocalyptic number.

2132413403 is a deficient number, since it is larger than the sum of its proper divisors (52010125).

2132413403 is an equidigital number, since it uses as much as digits as its factorization.

2132413403 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 52010124.

The product of its (nonzero) digits is 1728, while the sum is 23.

The square root of 2132413403 is about 46178.0619233852. The cubic root of 2132413403 is about 1287.1341147515.

Adding to 2132413403 its reverse (3043142312), we get a palindrome (5175555715).

The spelling of 2132413403 in words is "two billion, one hundred thirty-two million, four hundred thirteen thousand, four hundred three".

Divisors: 1 41 52010083 2132413403