Base | Representation |
---|---|
bin | 11111000010000110110… |
… | …011100010001011101001 |
3 | 21112212112011002200222012 |
4 | 133002012303202023221 |
5 | 234414443222410423 |
6 | 4311404222205305 |
7 | 310033650053051 |
oct | 37020663421351 |
9 | 7485464080865 |
10 | 2132565435113 |
11 | 752463657323 |
12 | 2a537ba23835 |
13 | 12613ba99139 |
14 | 75306960561 |
15 | 3a716195078 |
hex | 1f086ce22e9 |
2132565435113 has 4 divisors (see below), whose sum is σ = 2133429874320. Its totient is φ = 2131700995908.
The previous prime is 2132565435073. The next prime is 2132565435131. The reversal of 2132565435113 is 3115345652312.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 2132565435113 - 214 = 2132565418729 is a prime.
It is a Duffinian number.
It is a Curzon number.
It is not an unprimeable number, because it can be changed into a prime (2132565435163) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 432215903 + ... + 432220836.
It is an arithmetic number, because the mean of its divisors is an integer number (533357468580).
Almost surely, 22132565435113 is an apocalyptic number.
It is an amenable number.
2132565435113 is a deficient number, since it is larger than the sum of its proper divisors (864439207).
2132565435113 is an equidigital number, since it uses as much as digits as its factorization.
2132565435113 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 864439206.
The product of its digits is 324000, while the sum is 41.
The spelling of 2132565435113 in words is "two trillion, one hundred thirty-two billion, five hundred sixty-five million, four hundred thirty-five thousand, one hundred thirteen".
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